Pentomino mit zwei Symmetrieachsen - Typ 11
Author: Mag. G. Wengler

Dieser Typ ist 2-fach symmetrisch. Überlege, wie viele unterschiedliche Positionen es deshalb gibt.

hat 2 Achsen => ein Zentrum

drehen

2-fach symmetrisches Pentomino

A = (-2, 2)
a = 1
b = 0
B: (a + x(A), b + y(A))
c = 1
d = 1
C: (c + x(A), d + y(A))
e = 2
f = 1
D: (e + x(A), f + y(A))
g = 2
h = 2
E: (g + x(A), h + y(A))
i = 3
j = 2
F: (i + x(A), j + y(A))
k = 3
l = 3
G: (k + x(A), l + y(A))
m = 1
n = 3
H: (m + x(A), n + y(A))
o = 1
p = 2
I: (o + x(A), p + y(A))
q = 0
r = 2
J: (q + x(A), r + y(A))
s = Line(I, D)
t = false
K = Point(s)
L = Point(s)
M = (2, 5)
u = 0
v = -1
N: (u + x(M), v + y(M))
w_4 = 1
z = -1
O: (w_4 + x(M), z + y(M))
l_1 = 1
m_1 = -2
P: (l_1 + x(M), m_1 + y(M))
n_1 = 2
o_1 = -2
Q: (n_1 + x(M), o_1 + y(M))
p_1 = 2
q_1 = -3
R: (p_1 + x(M), q_1 + y(M))
r_1 = 3
s_1 = -3
S: (r_1 + x(M), s_1 + y(M))
t_1 = 3
u_1 = -1
T: (t_1 + x(M), u_1 + y(M))
v_1 = 2
w_1 = -1
U: (v_1 + x(M), w_1 + y(M))
z_1 = 2
a_2 = 0
V: (z_1 + x(M), a_2 + y(M))
W = (4, 1)
b_2 = 1
c_2 = 0
Z: (b_2 + x(W), c_2 + y(W))
d_2 = 1
e_2 = -2
A_1: (d_2 + x(W), e_2 + y(W))
f_2 = 0
g_2 = -2
B_1: (f_2 + x(W), g_2 + y(W))
h_2 = 0
i_2 = -3
C_1: (h_2 + x(W), i_2 + y(W))
j_2 = -2
k_2 = -3
D_1: (j_2 + x(W), k_2 + y(W))
l_2 = -2
w_2 = -2
E_1: (l_2 + x(W), w_2 + y(W))
z_2 = -1
a_3 = -2
F_1: (z_2 + x(W), a_3 + y(W))
b_3 = -1
c_3 = -1
G_1: (b_3 + x(W), c_3 + y(W))
d_3 = 0
e_3 = -1
H_1: (d_3 + x(W), e_3 + y(W))
I_1 = (1, -2)
i_3 = -2
j_3 = 0
J_1: (i_3 + x(I_1), j_3 + y(I_1))
k_3 = -2
l_3 = 1
K_1: (k_3 + x(I_1), l_3 + y(I_1))
m_3 = -3
n_3 = 1
L_1: (m_3 + x(I_1), n_3 + y(I_1))
o_3 = -3
p_3 = 3
M_1: (o_3 + x(I_1), p_3 + y(I_1))
q_3 = -2
r_3 = 3
N_1: (q_3 + x(I_1), r_3 + y(I_1))
s_3 = -2
t_3 = 2
O_1: (s_3 + x(I_1), t_3 + y(I_1))
u_3 = -1
v_3 = 2
P_1: (u_3 + x(I_1), v_3 + y(I_1))
f_4 = -1
g_4 = 1
Q_1: (f_4 + x(I_1), g_4 + y(I_1))
h_4 = 0
i_4 = 1
R_1: (h_4 + x(I_1), i_4 + y(I_1))
S_1 = (2, 2)
T_1 = (5, 5)
U_1 = (2, 1)
V_1 = (5, -2)
W_1 = (-2, -2)
Z_1 = (1, 1)
u_4 = false
A_2 = (1.5, 1.5)
w = 0.7853981633974483 rad (slider from 0 to 90*°, step 0.017453292519943295)
A' = Rotate(A, w, (1.5, 1.5))
B' = Rotate(B, w, (1.5, 1.5))
C' = Rotate(C, w, (1.5, 1.5))
D' = Rotate(D, w, (1.5, 1.5))
E' = Rotate(E, w, (1.5, 1.5))
F' = Rotate(F, w, (1.5, 1.5))
G' = Rotate(G, w, (1.5, 1.5))
H' = Rotate(H, w, (1.5, 1.5))
I' = Rotate(I, w, (1.5, 1.5))
J' = Rotate(J, w, (1.5, 1.5))
B_2 = (2, 3)
a_1 = 0
b_1 = -5
C_2: (a_1 + x(B_2), b_1 + y(B_2))
c_1 = 1
d_1 = -5
D_2: (c_1 + x(B_2), d_1 + y(B_2))
e_1 = 1
f_1 = 0
E_2: (e_1 + x(B_2), f_1 + y(B_2))
Vieleck1, b_4, c_4, d_4, e_4 = Polygon(B_2, C_2, D_2, E_2)
g_1 = Segment((2.5, 4), (2.5, -3))
h_1 = Segment((0, 0.5), (5, 0.5))
F_2 = Intersect(h_1, g_1)
G_2 = Rotate(B_2, 90*°, (2.5, -3.5))
H_2 = Rotate(C_2, 90*°, (2.5, -3.5))
I_2 = Rotate(D_2, 90*°, (2.5, -3.5))
J_2 = Rotate(E_2, 90*°, (2.5, -3.5))
Vieleck1', g_3, h_3, i_1, j_1 = Polygon(G_2, H_2, I_2, J_2)
k_1 = Segment(B_2, D_2)
m_2 = Segment(E_2, C_2)
K_2 = Rotate(B_2, w, (2.5, -3.5))
L_2 = Rotate(C_2, w, (2.5, -3.5))
M_2 = Rotate(D_2, w, (2.5, -3.5))
N_2 = Rotate(E_2, w, (2.5, -3.5))
Vieleck1'_1, k_4, l_4, m_4, n_2 = Polygon(K_2, L_2, M_2, N_2)
O_2 = (2.5, -3.5)
p_2 = Circle(O_2, B_2)
Liste1 = Rotate({g_1, h_1, k_1, m_2}, 90*°, (2.5, -3.5))
P_2 = Rotate(F_2, 90*°, (2.5, -3.5))