Lastarmlänge [cm]

Last [N]

Tabelle bei indirekter Proportion

vervielfachen

÷ 3

x 3

÷ 2

x 2

x 6

÷ 6

teilen

x 2

÷ 2

Andere Werte

Rechne nach!

y

x

?

Last x Lastarm ist auf beiden Seiten gleich:
z.B.: 80 x 40 = 20 x 160 = 320

Überlege, welche Last man bei Länge 0 bräuchte!

masse = Random(2, 20)
preis = Random(10, 90)
untenT = Sequence(Text[(k * masse / 10), (k - 0.1, 0.2)], k, 0, 10)
s_{10} = Sequence(Segment[(k, 0.5), (k, 2)], k, 0, 10)
c = true
A = (1, 3)
B = (3, 3)
d = Semicircle(A, B)
C = (1, -0.5)
D = (3, -0.5)
e = Semicircle(D, C)
E = (6, -0.5)
f = Semicircle(E, D)
F = (6, 3)
g = Semicircle(B, F)
h = Semicircle(A, F)
k = Semicircle(E, C)
i = false
G = (6, 3)
H = (3, 3)
p = Semicircle(H, G)
I = (6, -0.5)
J = (3, -0.5)
q = Semicircle(I, J)
K = (1, 3)
N = (1, -0.5)
obenT = Sequence(Text[preis / ((k * masse / 10)), (k - 0.2, 2.1)], k, 1, 10)
Text19: "x·y = " + preis + ""
L = (-1.3077994814524398, 2.539324342172178)
M = (-0.4502184958988468, 2.539324342172178)
O = (-0.4502184958988468, 0.012523224023204181)
P = (-1.3077994814524398, 0.012523224023204181)
Vieleck1, l, m, o, p_1 = Polygon(L, M, O, P)
Q = (5, 7)
R = (4.989295183898229, 5.597519392440966)
S = (7.990828633335805, 5.597519392440966)
T = (8, 7)
Vieleck2, q_1, r, s, t = Polygon(Q, R, S, T)